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harleyzhao(赵政)
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README.md

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> [c++面向对象](https://github.com/zhaozhengcoder/CoderNoteBook/blob/master/note/c%2B%2B%E9%9D%A2%E5%90%91%E5%AF%B9%E8%B1%A1.md)
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> [c++类型转换cast](https://github.com/zhaozhengcoder/CoderNoteBook/blob/master/note/c%2B%2B%E9%9D%A2%E5%90%91%E5%AF%B9%E8%B1%A1.md)
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> [c++类型转换cast](https://github.com/zhaozhengcoder/CoderNoteBook/blob/master/note/c%2B%2B%E7%9A%84%E7%B1%BB%E5%9E%8B%E8%BD%AC%E6%8D%A2cast.md)
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> [智能指针-todo]()
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> [移动构造函数,右值引用,move-todo]
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note/TCP和网络编程.md

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* 向一个没有监听的端口建立tcp连接,会发生什么?
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* accept 出现在三次握手的什么时候?
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* 为什么需要四次挥手?(为什么上次不可以?)
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* 什么时候会出现rst包?
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* 服务器已经close了fd,然后client取从这个fd上面接受和发送数据,分别会出现什么问题?

note/c++智能指针.md

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# C++ 智能指针
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## 目录
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* [智能指针如何解决循环引用问题](#智能指针如何解决循环引用问题)
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* [enable_shared_from_this](#enable_shared_from_this实现)
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---
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## 智能指针如何解决循环引用问题
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## enable_shared_from_this

note/c++的类型转换cast.md

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```
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* dynamic_cast
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* dynamic_cast
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dynaic_cast 是如何实现的?

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