std::lexicographical_compare
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<metanoindex/>
<tbody> </tbody>| Elemento definito nell'header <algorithm>
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template< class InputIt1, class InputIt2 > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2 ); |
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template< class InputIt1, class InputIt2, class Compare > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, Compare comp ); |
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Controlla se il primo intervallo è
[first1, last1) lexicographically' inferiore al [first2, last2) secondo intervallo. La prima versione utilizza operator< di confrontare gli elementi, la seconda versione utilizza la funzione di confronto dato comp.Original:
Checks if the first range
[first1, last1) is lexicographically less than the second range [first2, last2). The first version uses operator< to compare the elements, the second version uses the given comparison function comp.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Confronto lessicografico è un'operazione con le seguenti proprietà:
Original:
Lexicographical comparison is a operation with the following properties:
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
- Due campi sono confrontati elemento per elemento.Original:Two ranges are compared element by element.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - L'elemento mismatching prima definisce quale intervallo è lexicographically meno o' superiore rispetto agli altri.Original:The first mismatching element defines which range is lexicographically less or greater than the other.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Se un intervallo è un prefisso di un altro, la gamma più breve è lexicographically' di meno rispetto agli altri.Original:If one range is a prefix of another, the shorter range is lexicographically less than the other.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Se due serie hanno elementi equivalenti e sono della stessa lunghezza, gli intervalli sono uguali lessicograficamente'.Original:If two ranges have equivalent elements and are of the same length, then the ranges are lexicographically equal.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Un campo a vuoto è lexicographically' meno di qualsiasi non vuota gamma.Original:An empty range is lexicographically less than any non-empty range.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Due campi sono vuoti lessicografico' uguali.Original:Two empty ranges are lexicographically equal.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Parametri
| first1, last1 | - | la prima gamma di elementi da esaminare
Original: the first range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| first2, last2 | - | il secondo intervallo di elementi da esaminare
Original: the second range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-InputIt1, InputIt2 must meet the requirements of InputIterator.
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Valore di ritorno
true se il primo intervallo è lexicographically meno della seconda.Original:
true if the first range is lexicographically less than the second.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Complessità
Alla maggior parte delle applicazioni di 2·min(N1, N2) l'operazione di confronto, dove
N1 = std::distance(first1, last1) e N2 = std::distance(first2, last2).Original:
At most 2·min(N1, N2) applications of the comparison operation, where
N1 = std::distance(first1, last1) and N2 = std::distance(first2, last2).The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Possibile implementazione
| First version |
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template<class InputIt1, class InputIt2>
bool lexicographical_compare(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2)
{
for ( ; (first1 != last1) && (first2 != last2); first1++, first2++ ) {
if (*first1 < *first2) return true;
if (*first2 < *first1) return false;
}
return (first1 == last1) && (first2 != last2);
}
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| Second version |
template<class InputIt1, class InputIt2, class Compare>
bool lexicographical_compare(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
Compare comp)
{
for ( ; (first1 != last1) && (first2 != last2); first1++, first2++ ) {
if (comp(*first1, *first2)) return true;
if (comp(*first2, *first1)) return false;
}
return (first1 == last1) && (first2 != last2);
}
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Esempio
#include <algorithm>
#include <iostream>
#include <vector>
#include <cstdlib>
#include <ctime>
int main()
{
std::vector<char> v1 {'a', 'b', 'c', 'd'};
std::vector<char> v2 {'a', 'b', 'c', 'd'};
std::srand(std::time(0));
while (!std::lexicographical_compare(v1.begin(), v1.end(),
v2.begin(), v2.end())) {
for (auto c : v1) std::cout << c << ' ';
std::cout << ">= ";
for (auto c : v2) std::cout << c << ' ';
std::cout << '\n';
std::random_shuffle(v1.begin(), v1.end());
std::random_shuffle(v2.begin(), v2.end());
}
for (auto c : v1) std::cout << c << ' ';
std::cout << "< ";
for (auto c : v2) std::cout << c << ' ';
std::cout << '\n';
}
Possible output:
a b c d >= a b c d
d a b c >= c b d a
b d a c >= a d c b
a c d b < c d a b